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PDP-10 Archives
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decuslib10-01
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43,50110/pert.tuk
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10' NAME--PERT
20'
30' DESCRIPTION--NETWORK ANALYSIS FOR PERT TIME
40'
50' SOURCE--UNKNOWN
60'
70' INSTRUCTIONS
72 REM THIS PROGRAM ANALYZES A PERT NETWORK, AND FOR EACH
74
76 REM EVENT IN THE NETWORK THE PROGRAM WILL DETERMINE THE
78
80 REM FOLLOWING VARIABLES;
82
84 REM 1) TE - THE EARLIEST EXPECTED TIME OF COMPLETION
86 REM OF THE EVENT WITHIN THE NETWORK.
88
90 REM 2) V - THE VARIANCE ASSOCIATED WITH THE TE OF
92 REM THE EVENT WITHIN THE NETWORK.
94
96 REM 3) TL - THE LATEST ALLOWABLE TIME FOR THE COMPLETION
98 REM OF THE EVENT WITHIN THE NETWORK WITHOUT CHANGING
100 REM THE TE OF THE FINAL EVENT.
102
104 REM 4) SLACK - TL-TE.
106
108
110 REM THE ANALYSIS IS ADOPTED FROM THE PROGRAM AS SET FORTH
112 REM ON PAGES 189-211, IN MC MILLAN AND GONZALES.
114
116 REM IN THIS PROGRAM NO EVENT CAN HAVE MORE THAN TWO
118 REM IMMEDIATE PREDECESSOR EVENTS AND TWO IMMEDIATE
120 REM SUCCESSOR EVENTS. TO USE THIS PROGRAM WITH MORE
122 REM COMPLEX NETWORKS, ENTER A 'DUMMY' EVENT OF
124 REM ZERO TIME FOR COMPLETION AND ZERO VARIANCE. FOR
126 REM EXAMPLE; IF EVENTS 1, 2, AND 3 PRECEED EVENT 5
128 REM THEN ENTER A 'DUMMY' EVENT 4, OF ZERO (0) TIME FOR
130 REM COMPLETION AND ZERO (0) VARIANCE, SUCH THAT EVENTS
132 REM 1 AND 2, OR 1 AND 3, OR 2 AND 3 PRECEED EVENT 4.
134 REM THEN EVENT 5 WILL HAVE ONLY TWO PRECEEDING EVENTS AS
136 REM ALLOWED BY THE PROGRAM. ( I.E. EVENT 5 WILL BE PRECEEDED
138 REM BY 1 AND 4, OR 2 AND 4, OR 3 AND 4 )
140
142
144 REM BEGINNING IN LINE 2000 ENTER THE DATA. FIRST ENTER
146 REM T, THE TOTAL NUMBER OF EVENTS IN THE NETWORK.
148 REM THEN, BEGINNING WITH THE FINAL EVENT AS NUMBER ONE,
150 REM ( 1 ) ENTER THE FOLLOWING DATA IN, IN ORDER ;
152
154 REM 1) THE NUMBER OF THE EVENT'S FIRST IMMEDIATE
156 REM PREDECESSOR.
158
160 REM 2) THE T(E) ASSOCIATED WITH THE EVENT'S FIRST
162 REM IMMEDIATE PREDECESSOR.
164
166 REM 3) THE VARIANCE ASSOCIATED WITH THE EVENT'S
168 REM FIRST IMMEDIATE PREDECESSOR.
170
172 REM 4) THE NUMBER OF THE EVENT'S SECOND IMMDEIATE
174 REM PREDECESSOR. IF NONE, ENTER ZERO.
176
178 REM 5) THE T(E) ASSOCIATED WITH THE EVENT'S SECOND
180 REM IMMEDIATE PREDECSSOR. IF NONE, ENTER ZERO.
182
184 REM 6) THE VARIANCE ASSOCIATED WITH THE EVENT'S SECOND
186 REM IMMEDIATE PREDECESSOR. IF NONE ENTER ZERO.
188
190 REM 7) THE TE OF THE EVENT, WHERE KNOWN.
192 REM IF UNKNOWN, ENTER ZERO.
194
196 REM 8) THE VARIANCE ASSOCIATED WITH THE EVENT, WHERE KNOWN.
198 REM IF UNKNOWN, ENTER ZERO.
200
202 REM THE LAST EVENT MUST BE LABELED 1, THE OTHER EVENTS
204 REM NEED NOT HAVE ANY ORDER. REMEMBER WHEN ENTERING
206 REM THE DATA, THAT YOU ENTER T, THE 8 PIECES OF DATA
208 REM FOR EVENT 1, THEN 8 FOR EVENT 2, THE 8 FOR EVENT 3 ETC.
210
212
214 REM T(E) = THE MEAN TIME REQUIRED FOR THE COMPLETION OF
216 REM THE EVENT'S IMMEDIATE PREDECESSOR.
218 REM T(E) IS DEFINED AS; T(E) = ( A + 4*M + B )/6, WHERE
220
222 REM A - MOST OPTOMISTIC TIME FOR COMPLETION
224 REM B - MOST PESSEMISTIC TIME FOR COMPLETION
226 REM M - MOST LIKELY TIME FOR COMPLETION
228
230 REM THE VARIANCE ASSOCIATED WITH THE COMPLETION OF THE
232 REM EVENT'S IMMEDIATE PREDECESSOR IS DEFINED AS
234 REM VARIANCE = V = ((B-A)/6)^2, WHERE A AND B ARE DEFINED
236 REM ABOVE.
238
240
242 REM AT LEAST ONE EVENT IN THE NETWORK MUST HAVE ITS
244 REM EARLIEST COMPLETION TIME SPECIFIED ( I.E. AT LEAST
246 REM ONE EVENT'S TE MUST BE KNOWN)
248 REM IF HOWEVER, NO EVENT HAS A SPECIFIED TE, LET THE
250 REM THE TE OF THE INITIAL EVENT IN THE NETWORK BE
252 REM SPECIFIED AS ONE, ( 1 ). THUS, THE INITIAL EVENT IN
254 REM THE NETWORK WOULD HAVE IN ITS SEVENTH DATA LOCATION
256 REM A ONE, INSTEAD OF A ZERO. ( I.E. ASSUME EVENT NUMER
258 REM 9 IS THIS FIRST EVENT IN THE NETWORK AND STARTS AT
260 REM TIME ZERO, ITS DATA FORM WOULD LOOK LIKE
262 REM XXXX DATA ------0-, HOWEVER, FOR THE PROGRAM TO
264 REM OPERATE THE EVENT WOULD HAVE TO BE ASSIGNED AN
266 REM ARBITRARY TE, SAY 1, ITS CORRECT DATA STATEMENT
268 REM WOULD TAKE THE FORM, XXXX DATA ------1-.
270
272
274
276 REM DON'T FORGET TO ENTER 'T', THE NUMBER OF EVENTS
278 REM IN THE NETWORK.
280 REM EACH EVENT IN THE NETWORK MUST HAVE 8 PIECES OF DATA
282 REM ENTERED FOR IT.
284
286 REM IF THERE ARE MORE THAN TEN EVENTS IN THE NETWORK
288 REM ENTER A DIM STATEMENT IN LINE 610 SUCH THAT E(T,13),
290 REM P(T), AND S(T) ARE DIMENSIONED, WHERE T= NUMBER OF EVENTS.
292 REM
300'
310' THIS PROGRAM WAS WRITTEN FOR STUDENT USE AT AMOS TUCK SCHOOL
320' OF HANOVER, N.H. WHICH DOES NOT ASSUME RESPONSIBILITY FOR ITS
330' ACCURACY.
340'
350' * * * * * * * * * * * MAIN PROGRAM * * * * * * * * * * *
360'
600 READ T
610 DIME(21,13),P(21),S(21)
620 FOR N= 1 TO T
630 FOR I= 1 TO 8
640 READ E(N,I)
650 NEXT I
660 FOR I= 9 TO 13
670 LET E(N,I) = 0
680 NEXT I
690 NEXT N
695
700
710
720 REM FIND TE
730
740 FOR I= 1 TO T
750 LET P(I) = 0
760 NEXT I
770 LET I = 1
780 LET P(1) = 1
790 LET N = 1
800 LET N = E(N,1)
810 LET I = I + 1
820 LET P(I) = N
830 IF E(N,7) = 0 THEN 800
840 LET I = I - 1
850 IF I = 0 THEN 1250
860 LET N = P(I)
870 IF S(N) = 2 THEN 1060
880 IF E(N,4)<> 0 THEN 920
890 LET E(N,7) = E(N,2) + E(P(I+1),7)
900 LET E(N,8) = E(N,3) + E(P(I+1),8)
910 GO TO 840
920 LET A = E(P(I+1),7) + E(N,2)
930 LET F = E(P(I+1),8) + E(N,3)
940 LET N = E(N,4)
950 LET I = I + 1
960 LET P(I) = N
970 IF E(N,7) <> 0 THEN 1000
980 LET S(P(I-1)) = 2
990 GO TO 800
1000 LET I = I - 1
1010 IF I = 0 THEN 1120
1020 LET N=P(I)
1030 LET B = E(P(I+1),7) + E(N,5)
1040 LET G = E(P(I+1),8) + E(N,6)
1050 GO TO 1140
1060 LET B = E(P(I+1),7) + E(N,5)
1070 LET G = E(P(I+1),8) + E(N,6)
1080 LET N = E(N,1)
1090 LET C = E(N,7)
1100 LET H = E(N,8)
1110 LET N = P(I)
1120 LET A = C + E(N,2)
1130 LET F = H + E(N,3)
1140 IF A > B THEN 1180
1150 LET E(N,7) = B
1160 LET E(N,8) = G
1170 GO TO 840
1180 LET E(N,7) = A
1190 LET E(N,8) = F
1200 GO TO 840
1210
1220
1230 REM FIND SUCCESSOR EVENTS AND RECORD TE'S
1240
1250 FOR I = 1 TO T
1260 LET N = E(I,1)
1270 IF N = 0 THEN 1340
1280 IF E(N,9) <> 0 THEN 1320
1290 LET E(N,9) = I
1300 LET E(N,10) = E(I,2)
1310 GO TO 1340
1320 LET E(N,11) = I
1330 LET E(N,12) = E(I,2)
1340 LET N = E(I,4)
1350 IF N = 0 THEN 1420
1360 IF E(N,9) <> 0 THEN 1400
1370 LET E(N,9) = I
1380 LET E(N,10) = E(I,5)
1390 GO TO 1420
1400 LET E(N,11) = I
1410 LET E(N,12) = E(I,5)
1420 NEXT I
1430
1440
1450 REM FIND TL
1460
1470 LET E(1,13) = E(1,7)
1480 FOR K= 1 TO T
1490 IF E(K,13) = 0 THEN 1520
1500 NEXT K
1510 GO TO 1810
1520 LET N = K
1530 LET I = 1
1540 LET P(1) = N
1550 IF E(N,13) <> 0 THEN 1690
1560 LET A = E(N,9)
1570 IF E(A,13) = 0 THEN 1730
1580 LET B = E(N,11)
1590 IF B = 0 THEN 1680
1600 IF E(B,13) = 0 THEN 1770
1610 LET T1 = E(A,13) - E(N,10)
1620 LET T2 = E(B,13) - E(N,12)
1630 IF T1 < T2 THEN 1660
1640 LET E(N,13) = T2
1650 GO TO 1690
1660 LET E(N,13) = E(A,13) - E(N,10)
1670 IF I = 1 THEN 1480
1680 LET E(N,13) = E(A,13) - E(N,10)
1690 IF I = 1 THEN 1480
1700 LET I = I - 1
1710 LET N = P(I)
1720 GO TO 1550
1730 LET N = A
1740 LET I = I + 1
1750 LET P(I) = N
1760 GO TO 1550
1770 LET N = B
1780 LET I = I + 1
1790 LET P(I) = N
1800 GO TO 1550
1810
1820
1830 REM PRINT RESULTS
1840
1850 PRINT "EVENT NUMBER","TE","V","TL","TOTAL SLACK"
1855 PRINT "----- ------","--","-","--","----- -----"
1860 PRINT
1870 FOR N = T TO 1 STEP -1
1880 PRINT N,E(N,7),E(N,8),E(N,13),E(N,13)-E(N,7)
1890 NEXT N
1900
1910
2000 DATA 21
2001 DATA 2,4,1.77,3,8,0,0,0
2002 DATA 4,0,0,5,10,4,0,0
2003 DATA 9,0,0,0,0,0,0,0
2004 DATA 6,6,.11,0,0,0,0,0
2005 DATA 9,0,0,0,0,0,0,0
2006 DATA 7,12,.11,8,10,.44,0,0
2007 DATA 10,24,21.77,0,0,0,0 ,0
2008 DATA 11,20,5.44,14,0,0,0,0
2009 DATA 7,12,.11,8,10,.44,0,0
2010 DATA 15,0,0,16,30,44.44,0,0
2011 DATA 15,0,0,16,30,44.44,0,0
2012 DATA 21,0,0,0,0,0,0,0
2013 DATA 20,40,177.59,0,0,0,0,0
2014 DATA 13,10,2.77,12,28,75.17,0,0
2015DATA 20,40,177.59,0,0,0,0,0
2016 DATA 17,8,1.77,0,0,0,0,0
2017 DATA 18,20,.44,0,0,0,0,0
2018 DATA 19,10,0,0,0,0,0,0
2019 DATA 0,0,0,0,0,0,1,0
2020 DATA 21,0,0,0,0,0,0,0
2021 DATA 19,10,0,0,0,0,0,0
9999 END